O20.5 -118
O20.5 @ -1181 -192
A. Vrancken αναμένεται να κερδίσει με απόδοση -192O20.5 -118
Ο αναμενόμενος αριθμός γκέιμ είναι άνω του 20.5
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14 Mar 25 | A. Vrancken V. Allen | 2 1 |
14 May | A. Vrancken Peeters E. Andreeva |
1 2 | L |
13 May | A. Vrancken Peeters C. Alves |
2 0 | W |
12 May | A. Rame A. Vrancken Peeters |
0 2 | W |
11 May | A. Vrancken Peeters V. Borodulina |
2 0 | W |
06 May | A. Vrancken Peeters C. Gennaro |
1 2 | L |
23 Apr | A. Vrancken Peeters J. L. S. Steur |
0 2 | L |
22 Apr | A. Vrancken Peeters E. Chiesa |
2 0 | W |
14 Apr | G. Minnen A. Vrancken Peeters |
2 0 | L |
13 Apr | J. Teichmann A. Vrancken Peeters |
0 2 | W |
12 Apr | A. Vrancken Peeters C. Werner |
2 0 | W |
05 May | V. Allen J. Otzipka |
0 2 | L |
01 May | V. Allen Y. L. Miyazaki |
1 2 | L |
30 Apr | V. Allen E. Adeshina |
2 0 | W |
29 Apr | V. Allen S. Leon |
2 0 | W |
21 Apr | L. Glushko V. Allen |
2 1 | L |
22 Mar | V. Allen S. Shapatava |
0 2 | L |
02 Mar | V. Allen A. Ozerova |
2 1 | W |
04 Feb | V. Allen N. Bains |
0 2 | L |
13 Jan | M. Hageman V. Allen |
0 2 | W |
31 Oct | K. Cross V. Allen |
2 0 | L |